Applets:Periodendauer periodischer Signale

Reset

mit Gitter

$x(t)=A_1\cdot cos\Big(2\pi f_1\cdot t- \frac{2\pi}{360}\cdot \phi_1\Big)+A_2\cdot cos\Big(2\pi f_2\cdot t- \frac{2\pi}{360}\cdot \phi_2\Big)$

x(t)=0.5

x(t+T₀)=0.276

x(t+2T₀)=0.276

x_max=0.88

T₀=1

0,0

A₁=0.50V

f₁=1.00kHz

ϕ₁=0.00Grad

A₂=0.50V

f₂=2.00kHz

ϕ₂=90.00Grad

t=0.00

0,0

–o+←↓↑→

t/T

x(t)