Period $T_0$ of Periodic Signal

© 2017 Institute for Communications Engineering, Technical University of Munich
Authors: David Jobst, Carolin Mirschina & Tasnad Kernetzky
$A_1=1$ V
$f_1=2 $ kHz
$\varphi_1=0^{\circ}$
$A_2=0.5$ V
$f_2=2.5 $ kHz
$\varphi_2=90^{\circ}$
$t_*=1$ ms
$T_0 =$ 2 $\\ $ ms
$x_{\text{max}} =$ 1.5 $\\ $ V,    $x(t_*)=x(t_*+T_0)=x(t_*+2T_0) =$ 1 $\\ $ V
1234567891011120.511.52−0.5−1−1.5−2
–o+←↓↑→
$t \ \text{[ms]}$
$x(t) \ \text{[V]}$
Exercises

* First select the number (1, 2, ... ) of the exercise.
* An exercise description is displayed. Parameter values are adjusted.
* Solution after pressing „Show solution”.
* The number 0 corresponds to a „Reset”: Same setting as at the program start.
* $A_1'$ and $A_2'$ denote the signal amplitudes normalized to $1\ \rm V$.
* $f_0'$, $f_1'$ and $f_2'$ are the frequencies normalized to $1\ \rm kHz$.